**Clearly NOT 17 Degrees!!!**

In order to get 17 Degrees, you show the exit wound in JFK’s neck as being 38 inches from Connally’s entrance wound in his back:

7.8 / tan(11.4) = 38.7

As I understand it, this horizontal distance is more like 28 inches. Using 28 inches, one gets:

atan(7.8/28.0) = 15.6 degrees.

15.6 degrees is pretty close to 17 degrees.

**Clearly NOT 38 inches.**Also, I should note that you did not include the 3 inches difference in height of the seats the two men were sitting in. While Connally was about 1.5 inches taller than JFK, this difference would not only be in the length of their respective torsos. Some would be in their torsos, and some in the legs. So Connally might have a torso that was 0.5 inches longer while his legs may have been 1.0 inches longer. Longer legs would make no difference, only longer torsos.

In any case, between an extra 1.5 inches to 3.0 inches, the math says the angle (with a horizontal distance of 28 inches) is 18.4 to 21.1 degrees. Not 11.4 degrees.

**Question:**

**Should we have more confidence in your drawings of the sniper’s nest, and the angles you show, than your poor calculations of the angle needed by a bullet to cause both the wounds in JFK and Connally?**

If so, why?