What?s the MINIMUM number of people required for your CT to work?

[Steve Howsley]

I think I heard someone say something like that as well about some politicians in those parties like Labour and the Tories.

If you recall what exactly was said I'd like to hear it. 

[Mitch Todd]

Yes, I've now had to look at a couple of Mitch's posts to see what he's been saying on other issues. Often a single word response to a question comes over as ambiguous or negative. His point that it takes two minimum to make a conspiracy is certainly a truism.

Something like that. It's always fun to ask some of the wilder truthers how they think it was done from a to z, then have the[m] figure up how many people it would take to do that. Most of these people swear "it would have been a small plot," but have never stopped to really figure out the cast they would need.

[Jerry Freeman]

Two.

       

                                   

[Colin Crow]

Of course we can only comment relating to conspiracies, successful or not that have been eventually unveiled. One might argue that the most successful conspiracies have never been discovered.

[Bill Chapman]

Of course we can only comment relating to conspiracies, successful or not that have been eventually unveiled. One might argue that the most successful conspiracies have never been discovered.

And you lot are just the ones to dream them up.

To wit, the accused:

42 groups
84 shooters
214 people

Yield: SFA

[John Iacoletti]

Based on the typical responses of any number of CT's at a least a Hundred, but ask any of these same CT's how big the Conspiracy was and they will always say it was only a small conspiracy! Go figure?
Caprio, Weidmann and Iacoletti are classic examples of this Tardis like logic.

No, that would be the strawman conspiracy that the ODIA nuts like to pretend that a conspiracy would have to be.

[John Iacoletti]

5) Alex Hidell**

** In charge of weapon procurement

Alex?  Mr. "does his research" strikes again!

[Jack Trojan]

Ok, here we go, minimal:

Allen Dulles - 1
James Angleton - 1
  -CIA underlings (Oswald/de Mohrenschildt/etc.)- ~10
J. Edger Hoover - 1
  -FBI underlings - ~20
  -DPD stooges - ~6
  -SS sellouts - ~5
Lyndon Johnson - 1
Assassins - 5
========
Total = ~50